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(4/t-3)+(t/2)=(12/t^2-9)
We move all terms to the left:
(4/t-3)+(t/2)-((12/t^2-9))=0
Domain of the equation: t-3)!=0
t∈R
Domain of the equation: t^2-9))!=0We add all the numbers together, and all the variables
t∈R
(4/t-3)+(+t/2)-((12/t^2-9))=0
We get rid of parentheses
4/t+t/2-((12/t^2-9))-3=0
We calculate fractions
We do not support etpression: t^3
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